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Even Count

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The objective is to identify and enumerate all numerical elements in the nums array that satisfy the condition of even parity. This involves filtering the collection based on divisibility by two to isolate elements that lack a remainder.

The resulting output should be a single non-negative integer representing the frequency of even numbers discovered. This count serves as a precise statistical measure of the parity distribution within the given sample set.

Example 1:

Input: nums = [1, 2, 3, 4, 5, 6]
Output: 3

Example 2:

Input: nums = [1, 3, 5]
Output: 0

Example 3:

Input: nums = [2, 4, 6, 8]
Output: 4

Algorithm Flow

Recommendation Algorithm Flow for Even Count - Budibadu
Recommendation Algorithm Flow for Even Count - Budibadu

Best Answers

java
class Solution {
    public int count_even(int[] nums) {
        int count = 0;
        for (int num : nums) {
            if (num % 2 == 0) count++;
        }
        return count;
    }
}