Linked List Searching and Pointer Techniques Quiz

Linked List
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A 30-question quiz covering searching in linked lists, the fast–slow pointer technique, and finding the middle node.

30 Questions
~60 minutes
1

Question 1

What is the time complexity of searching for a value in a singly linked list?

A
O(n)
B
O(1)
C
O(log n)
D
O(n log n)
2

Question 2

Which situation allows search to terminate early?

A
When the target value is found
B
When values are sorted
C
When the tail is reached once
D
When the list is circular
3

Question 3

What is required when searching by value?

A
Checking each node sequentially
B
Maintaining predecessor pointers
C
Reverse traversal
D
Random access to nodes
4

Question 4

What should a search function return if the value is not found?

A
An indication of failure (like null or -1)
B
The head node
C
The last visited node
D
A new default node
5

Question 5

Why can searching in a linked list be slower than searching in an array?

A
The lack of random indexing
B
Values are automatically sorted
C
Nodes reorder themselves
D
Linked lists store metadata
6

Question 6

If multiple nodes contain the same value, simple search usually returns:

A
The first matching node
B
The last matching node
C
All matching nodes
D
A count of duplicates
7

Question 7

What is the movement pattern of the fast pointer in the fast–slow pointer technique?

A
Two steps per iteration
B
One step per iteration
C
Three steps per iteration
D
Variable speed based on value
8

Question 8

Why must null checks be performed when using fast–slow pointers?

A
Fast may reach the end earlier
B
Slow may move too fast
C
Nodes become automatically reversed
D
Values get deleted during traversal
9

Question 9

In cycle detection, what condition indicates a cycle?

A
Fast and slow pointers eventually meet
B
Fast reaches the tail
C
Slow becomes null
D
Head changes automatically
10

Question 10

Why is the fast–slow method space efficient?

A
It requires only two pointers
B
It stores nodes in arrays
C
It deletes unused nodes
D
It compresses memory blocks
11

Question 11

Which pointer determines when the loop ends in middle-finding?

A
Fast pointer
B
Slow pointer
C
Tail pointer
D
Head pointer
12

Question 12

How many passes does the fast–slow technique require to find the middle?

A
One pass
B
Two passes
C
Depends on list size
D
It needs recursion
13

Question 13

In an odd-length list, where does the slow pointer end when fast reaches null?

A
Exactly at the middle node
B
At the last node
C
At the first node
D
Before the middle node always
14

Question 14

In an even-length list, where does the slow pointer end?

A
At the second of the two central nodes
B
At the first of the two central nodes
C
At the last node
D
At null always
15

Question 15

Why is the middle-finding technique efficient?

A
It does not require knowing the list length
B
It sorts the list first
C
It uses reverse traversal
D
It processes multiple lists at once
16

Question 16

What happens if the fast pointer moves three steps per iteration?

A
The slow pointer will no longer reach the correct middle
B
The traversal becomes impossible
C
The list becomes unsorted
D
The slow pointer moves faster automatically
17

Question 17

Which list property does the fast–slow pointer technique help identify besides the middle?

A
Existence of a cycle
B
Duplicate values
C
Sorted order
D
Node memory addresses
18

Question 18

What does slow pointer's pace represent in middle-finding?

A
Half the traversal progress compared to fast
B
The same speed as fast
C
Random movement
D
Length calculation
19

Question 19

What is required to safely advance the fast pointer two steps?

A
Checking fast and fast.next for null
B
Setting slow to null first
C
Ensuring sorted order
D
Removing duplicates
20

Question 20

How does the slow pointer move during middle-finding?

A
One step per iteration
B
Two steps per iteration
C
Variable based on value
D
It does not move
21

Question 21

What does this pattern represent?

plaintext
slow = slow.next
      fast = fast.next.next
A
Fast–slow pointer movement
B
Tail insertion
C
Node swapping
D
Head deletion
22

Question 22

Which node is the slow pointer pointing to in this diagram?

plaintext
[A] -> [B] -> [C] -> [D] -> [E]
                ^
               slow
A
B
B
A
C
C
D
D
23

Question 23

What is the termination condition for middle-finding?

plaintext
while fast != null and fast.next != null:
          slow = slow.next
          fast = fast.next.next
A
Fast becomes null or reaches end
B
Slow becomes null
C
Head changes
D
Values match
24

Question 24

What does this diagram show?

plaintext
[A] -> [B] -> [C] -> [D]
      slow: B   fast: C
A
An intermediate state of middle-finding
B
Tail deletion
C
Cycle creation
D
List reversal
25

Question 25

What search operation is this pseudocode performing?

plaintext
curr = head
      while curr != null:
          if curr.data == value:
              return curr
A
Linear search
B
Binary search
C
Skip list search
D
Middle-finding
26

Question 26

What is the role of slow here?

plaintext
while fast and fast.next:
          slow = slow.next
          fast = fast.next.next
      return slow
A
Returning the middle node
B
Returning the last node
C
Performing deletion
D
Counting nodes
27

Question 27

Why is the fast–slow method preferable over counting length first?

A
It avoids two separate passes
B
It sorts the list faster
C
It reduces space complexity dramatically
D
It deletes nodes automatically
28

Question 28

Which of the following may cause incorrect middle calculations?

A
Advancing fast without checking fast.next
B
Duplicate values
C
Large list size
D
Sorted or unsorted data
29

Question 29

Which action is required before performing any pointer technique?

A
Checking if the list is empty
B
Computing memory offsets
C
Sorting nodes in ascending order
D
Removing duplicate nodes
30

Question 30

What advantage does pointer-based middle-finding offer?

A
No need for stored length or secondary passes
B
It makes the list circular
C
It automatically detects duplicates
D
It converts the list to an array

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