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Chronicle Walkway Binding

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The museum’s chronicle walkway features illuminated stone tablets placed in a perfect numerical sequence. Your task in Chronicle Walkway Binding is to take a jumbled list of tablet IDs and return a brand-new list sorted in ascending order. This ensures guests follow history from earliest to most recent eras!

The "secret sauce" is In-Place Preservation. While tablets are rearranged, the original visitor log must stay untouched. Your routine creates a separate, orderly layout for the curators to guide the installation team. It must handle overlapping eras (duplicates) and ancient markers (negative values) with ease. If the walkway is already in order, just return a clean, sorted copy of the data. This vital routine turns a messy assortment of markers into a clear, professional path through history effortlessly!

When the task involves connectivity or route cost, build adjacency carefully and guard against revisiting stale states. Use a visited or best-distance structure to avoid repeated work, and ensure unreachable scenarios return the required fallback value instead of partial traversal results.

Examples

Example 1
Input
notes = 5
Output
0
Explanation

Example with input: notes = 5

Example 2
Input
notes = [[1, 3], [6, [7, 10]]]
Output
9
Explanation

Example with input: notes = [[1, 3], [6, [7, 10]]]

Example 3
Input
notes = [1, 4]
Output
3
Explanation

Example with input: notes = [1, 4]

Algorithm Flow

Recommendation Algorithm Flow for Chronicle Walkway Binding - Budibadu
Recommendation Algorithm Flow for Chronicle Walkway Binding - Budibadu

Best Answers

java
class Solution {
    private static class Result {
        int min, max, diameter;
        Result(int min, int max, int diameter) {
            this.min = min;
            this.max = max;
            this.diameter = diameter;
        }
    }
    
    public int chronicle_walkway_binding(Object notes) {
        return helper(notes).diameter;
    }
    
    private Result helper(Object node) {
        if (node instanceof Integer) {
            int val = (Integer) node;
            return new Result(val, val, 0);
        }
        Object[] pair = (Object[]) node;
        Result left = helper(pair[0]);
        Result right = helper(pair[1]);
        int nodeMin = Math.min(left.min, right.min);
        int nodeMax = Math.max(left.max, right.max);
        int nodeDiam = Math.max(Math.max(left.diameter, right.diameter), right.max - left.min);
        return new Result(nodeMin, nodeMax, nodeDiam);
    }
}