Find Target Range
Find Target Range requires locating the first and last positions of a target value in a sorted integer array. If the target does not appear, return [-1, -1]. Because duplicates may exist, a single binary search for any occurrence is not enough; you must identify both boundaries precisely.
The standard solution runs two binary searches: one for the leftmost index where value equals target, and one for the rightmost index. Each search maintains strict boundary movement rules to avoid off-by-one errors. This keeps complexity at O(log n) and works cleanly for large arrays where linear scans would be unnecessary.
Judge cases include absent targets, empty arrays, single-element matches, and repeated runs where range length is greater than one. Output must be a two-integer array only. Correctness depends on careful comparison branching and post-search validation, especially when insertion-point style results do not actually contain the target. With consistent boundary handling, the function remains fast, deterministic, and robust across all sorted-input edge scenarios.
After locating potential boundaries, validate both indices against array bounds and target equality before returning. This prevents insertion-point artifacts from being mistaken as real matches when the target is absent. The final output must always be a two-element integer array under every branch.
Examples
The target 8 first appears at index 3 and last at index 4.
All elements are equal to the target, so it spans from index 0 to 4.
The target 6 does not exist in the list.
Algorithm Flow

Best Answers
import java.util.Arrays;
class Solution {
public int[] find_target_range(int[] nums, int target) {
int first = findBound(nums, target, true);
if (first == -1) return new int[]{-1, -1};
int last = findBound(nums, target, false);
return new int[]{first, last};
}
private int findBound(int[] nums, int target, boolean isFirst) {
int l = 0, r = nums.length - 1;
int bound = -1;
while (l <= r) {
int mid = l + (r - l) / 2;
if (nums[mid] == target) {
bound = mid;
if (isFirst) r = mid - 1;
else l = mid + 1;
} else if (nums[mid] < target) {
l = mid + 1;
} else {
r = mid - 1;
}
}
return bound;
}
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